Question

the velocity of an object is given by v= (6t^3 i^+ t^2 j^ ) m/s . Find its acceleration at t= 2s.

Answer 1

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Answer 2

Answer:

Acceleration, $a=(72i+4j)\ m/s$

Explanation:

Given that,

Velocity of the object, $v=(6t^3i+t^2j)\ m/s$

We need to find the acceleration of the object. It can be calculated as :

$a=\dfrac{dv}{dt}$

$a=\dfrac{d(6t^3i+t^2j)}{dt}$

$a=18t^2i+2tj$

at t = 2s

$a=18(2)^2i+2(2)j$

$a=(72i+4j)\ m/s$

So, the acceleration of the object is $(72i+4j)\ m/s$ . Hence, this is the required solution.