Question

The velocity of car increases uniformly from 5ms-1 to 10ms-1 ,when it travels 50m. Find acceleration af car​

Answer 1

Explanation:

u=5m/s-1

v=10m/s-1

s=50m

v²=u²+2as

10²=5²+2×a×50

100=25+100a

75=100a

a=0.75m/s²

hope it helps....

Answer 2

Answer:

Given that,

• v = 20 m/s
• u = 5 m/s
• s = 50 m

We need to find : Acceleration (a) of the car.

Using the third equation of motion : v² - u² = 2as.

⇒ (10)² - (5)² = 2a*50

⇒ 100 - 25 = 100a

⇒ 75 = 100a

⇒ a = 75/100

⇒ a = 0.75 m/s²

Hence, Acceleration of the car is 0.75 m/s².

Important formulas related to rectilinear motion :

• Average velocity = ∆x/∆t
• v = lim (∆t ➜ 0) ∆x/∆t = dx/dt
• Average acceleration = ∆v/∆t
• a = lim (∆t ➜ 0) ∆v/∆t = dv/dt
• ∆x = x_2 - x_1
• v = u + at
• s = ut + ½at²
• v² - u² = 2as