Question

the velocity of electron in hydrogen atom is 7.29 *10^7 cm per second the potential energy of the electron is​

Answer 1

Answer:

-3.022 eV

Explanation:

Kinetic energy= -(potential energy)/2

kinetic energy= (mv^2)/2

m= mass of electron

v= velocity of electron

substituting values

potential energy= - mv^2

potential energy= -4.83611× 10^-19 J

= -3.022 eV