Question

The velocity of particle moving in a straight line is given by y = 20 - 5x² m/s, where x is position in metres. The acceleration of particle at x=2 m is O -10 m/s O 10 m/s 0 -16m/s? O om/s​

Answer 1

Answer:

Accln of particle is 0 m/s²

Explanation :

Velocity    y = 20 - 5$x^{2}$

          diff wrt t

               $\frac{dy}{dt}$  = - 10$x^{}$ $\frac{dx}{dt}$        But $\frac{dx}{dt}$ = velo =y

                 a = -10 $x^{}$ y

At x = 2m,      y = 20 - 5 x 4 = 0 m/s

               ∴   accln a = -10(2)(0) = 0