Physics, asked by Shobhit6338, 1 year ago

The velocity of particle varied with position x as v=(beta)( x^_2n) Then the acceleration of particle is

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Answered by nsaipranavi

0

a=dv/dt

Doing differentiation

a=beta (2n) x^2n-1

(using dx^n/dt=n x^n-1)

Answered by Anonymous

1

see the attachment....

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