Question

the velocity of the car increases from 15km/hr to 33km/hr in 20 sec find its acceleration plz help me step by step .
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Answer 1

Answer:

a=v-u/t

a=(33-15)/20

a=18/20

a=0.9

Answer 2

Answer: 0.25 m/s²

Given:

$\sf\text{Initial velocity of the car(u)=15km/h}\\\sf\text{Final velocity of the car(v)=30 km/h}\\\sf\text{Time taken by the car (t) = 20 s}$

To find:

$\sf\text{Accelaration(a) of the car.}$

Explanation:

$\sf\text{We know that 1 km = 1000 m and 1 hr = 3600 s. Therefore,}$

$\sf u=15\times\frac{1000}{3600}=15\times\frac{5}{18}=4.1\;m/s\\\\sf v=33\times\frac{1000}{3600}=33\times\frac{5}{18}=9.1\:m/s$

$\sf\text{We also know that,}$

$\sf\textbf\large{ `` Acceleration\; is\; the\; rate\; of\; change\; of\; the\; velocity\; of\; an \;object\; with\; respect\; to\; time."}$

$\fbox{\sf\textbf{Accleration(a)=}\large\text{ \frac{\textbf{Change\: in \:velocity}}{\textbf{Time}} }}$

$\fbox{\sf\large\text{ \bold{a=\frac{v-u}{t}} }}$

$\sf\text{Substituting the values of v,u and t in the above equation, we get:}$

$\sf a=\frac{9.1-4.1}{20} \\\\ a=\underline{0.25\:m/s^2}$

Therefore, the acceleration of the car is 0.25 m/s².