Question

The velocity of the particle is given by the expression v = 2t + 3t^2 (where v is in ms–1 and t is in seconds). Find out the distance travelled by the particle from t = 2 to t = 3 seconds.

Detailed explanation

Answer 1

Answer:

v= 2t+3t²

v=dx/dt

dx/dt=2t+3t²

dx=(2t+3t²)dt

Integrate with 3 and 2 as limits to find the distance x

X= t²+t³]³

²

X=24m