Question

the velocity of train increases uniformly from 20km/h to 60km/h in 4 hours the distance travelled by the train during time period is.

Answer 1

intial velocity u= 20 km /hr=5.56 m/s
final velocity v=60 km/hr=16.67 m/s
the train is under uniform accerleration
t=0.2 hr=12 minutes=720 secs
a=v-u/t=0.0154 m/s²
s=ut+(1/2)at²=7994.88 m=7.99488 km

Answer 2

Given,

Initial velocity of the train = 20km/h = 5.55 m/s

Final velocity of the train = 60km/h = 16.66 m/s

Time taken = 4 hours

And, uniform acceleration was happening.

To find,

The distance covered by the train.

Solution,

Firstly we have to calculate the value of acceleration by using the following mathematical formula,

=(Final velocity - Initial velocity)/time

= (16.66-5.55)/14400

= 0.00077 m/s²

So,the distance covered

= ut + 1/2 at²

= (5.55×14400) + (1/2 × 0.00077 × 14400 × 14400)

= 79920 + 79833.6

= 159753.6 metres

= 159.7 kilometres

Hence,the train travelled approximately 159.7 kilometres.