Question

The velocity – time graph below describes a 50 second journey of a car. Calculate the total distance travelled by the car and the maximum acceleration of the car during its 50 second journey. pls no spam answers

Answer 1

Answer: lets mark certain points ( given in file attached below!)

Here, distance travelled = highest point on the graph

Here, Distance= speed×time.

DistanceB=speedB×timeB

DistanceB=750m.

Total distance=750m.

maximum acceleration= (v-u)/t

v=25m/s, u=15m/s.

(25-15)/50

10/50

1/5=0.2m/s²

Answer 2

Answer:

Explanation:

Here, distance travelled = highest point on the graph

Here, Distance= speed×time.

DistanceB=speedB×timeB

DistanceB=750m.

Total distance=750m.

maximum acceleration= (v-u)/t

v=25m/s, u=15m/s.

(25-15)/50

10/50

1/5=0.2m/s²