Question

the velocity time graph of a particle moving along side line is shown in the figure by curve OABCD calculate the distance covered by the particle between (i) 0 to 18 sec (ii) 2sec to 12 sec and the maximum value of accelerated during the interval.

Answer 1

For first 8 sec distance is ( (20-0)*8 ) , second A to B distance is (10*2) next B to C distance is ( 0) because velocity is 0 ane last Cto D distance is( 10*4) than total distance is 20*8+10*2+10*4=220m