The velocity time graph of a particle of mass 50 gram moving indefinite directions is shown in the following figure answer the question based on the figure a what is the velocity of particle at point A B find the momentum of particle at time t is equal to 4 seconds calculate the distance travelled in 4 seconds
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(a) velocity of particle at point A = 2m/s
(b) momentum of particle at point at time t = 4 sec = mass × velocity of Particle at time t = 4 sec
mass = 50g = 0.05Kg and velocity = 2 m/s
So, momentum = 0.05 × 2 = 0.1 Kgm/s
c) distance travelled by particle = |area inclosed by v- t graph |
= |1/2 × 4 × 2 | = 4m
(b) momentum of particle at point at time t = 4 sec = mass × velocity of Particle at time t = 4 sec
mass = 50g = 0.05Kg and velocity = 2 m/s
So, momentum = 0.05 × 2 = 0.1 Kgm/s
c) distance travelled by particle = |area inclosed by v- t graph |
= |1/2 × 4 × 2 | = 4m
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