Question

the velocity time graph of an object moving along a straight line . find the distance covered by the object in time t =0 to t = 7s and the maximum value of acceleration during this interval​

Answer 1

Answer:

bhai dekh pehla wala ek triangle hai jo 1 right angle triangle hai uski area nikal uske baad square hai uska bhi area nikal uske baad Jo quadrilateral safe hai uska bhi area nikal aur uske baad Jo right angle triangle uska bhi square nikal aur FIR sare area on ko add kar de Shayad answer mil jayega u think ye +2 1st year ka question hai

Answer 2

Answer:

the object starts from rest at 0 after to sec it moves 20 m and from 2 sec to 3 sec it is at restand it increase its velocity and movesto 50 m per sec then it again come to rest after 7 sec

Explanation:

i am sure this will help you