Question

the velocity time graph of runner is given in the graph.
a)What is the total distance covered in 16seconds.

b)What is the acceleration of the runner at t =11seconds.

Answer 1

Answer:

The total distance is 130 m and the acceleration is zero at 11 second.

Explanation:

According to graph,

(a). The total distance covered in 16 seconds.

The total distance = Area of triangle +area of rectangular

$D = \dfrac{1}{2}\times h\times b+w\times l$

$D = \dfrac{1}{2}\times10\times6+10\times10$

$D=130\ m$

(b). The acceleration of the runner at t = 11 seconds.

The velocity is not changing at 11 second so the acceleration will be zero.

Hence, The total distance is 130 m and the acceleration is zero at 11 second.

Answer 2

Answer:

According to graph,

(a). The total distance covered in 16 seconds.

The total distance = Area of triangle +area of rectangular

D = \dfrac{1}{2}\times h\times b+w\times lD=

2

1

×h×b+w×l

D = \dfrac{1}{2}\times10\times6+10\times10D=

2

1

×10×6+10×10

D=130\ mD=130 m

(b). The acceleration of the runner at t = 11 seconds.

The velocity is not changing at 11 second so the acceleration will be zero.

Hence, The total distance is 130 m and the acceleration is zero at 11 second