Physics, asked by rj2308, 8 months ago

The velocity-time graph of the motion of a car is shown in the figure. The total distance travelled by the car in 11 s is 55 m 12 m Zero 45 m

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Answered by shrawan85356

0

Answer:

1 जवाब

12 × v0 × (6 - 1) = 90 12 × v0 × 5 = 90 v0 = 36 m/s Acceleration = v04 - 1 = 363 = 12 m/s2 Deceleration = v06 - 4 = 362 = 18 m/s2

Answered by aashukr06

3

Answer:

ZERO

Explanation:

AS u can see the slope of the graph is going simanteously upward and downward , so by calulating Distance covered will be zero

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