Question

The velocity time graph of the motion of a car is shown in figure the total distance travelled in 11 seconds ​

Answer 1

Answer:

★ Hence, Total Distance travelled by the car = 55 m ★

★ Given ★ :

➡ Velocity time graph of car in motion.

★ To Find ★ :

➡ Total Distance covered

★ Solution ★ :

Since, we can see that the velocity time graph is divided into two segments die to change in velocity and time.

So in order to find total distance, we can calculate the area of both segments separately and then add them.

We know that, from Velocity - Time Graph, Distance = Area under the slope.

• From graph the units of velocity are taken in m/sec and for time it is taken as sec.

➡ For the area of segment I :

• The area under the slope can be calculated by calculating the area of triangle.

So, we know that,

Area of triangle = 1/2 × base × height

=> Area of Triangle = 1/2 × b × h

And, Area of triangle = Area under the slope = Distance Travelled

Here,

Base, b = 5 sec

Height, h = 10 m/sec

Then,

Distance travelled = 1/2 × 5 × 10

=> Distance = (5 × 5) m = 25 m

➡ Hence, distance travelled in first case = 25 m

➡ For the area of segment II :

• The area under the slope can be calculated by calculating the area of triangle.

So, we know that,

Area of triangle = 1/2 × base × height

=> Area of Triangle = 1/2 × b × h

And, Area of triangle = Area under the slope = Distance Travelled

Here,

Base, b = 6 sec

Height, h = 10 m/sec

➡ * Note : Kindly remember it that since, distance is a scaler quantity it can never be represented using (-ve) sign. The distance travelled by object is always positive.

Distance travelled = 1/2 × 6 × 10

=> Distance Travelled = (5 × 6) m = 30 m

➡ Hence, distance travelled in the second segment = 30 m

Now, as given above,

Total Distance = Distance Travelled in First segment + Distance Travelled in Second segment

=> Total Distance = 25 m + 30 m = 55m

★ Hence, Total Distance travelled by the car = 55 m ★