Question

the velocity time relation of a moving object of mass 5kg is given as : v=3t²-4t+2.then find the acceleration of the object at time t=2second

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Answer 1

Answer:

A = 3t - 4t2dv/dt = 3t - 4t2

dv = (3t - 4t2)dt

Integrate

v = 3t2/2 - 4t3/3

At t = 1s

v = 3/2 - 4/3

v = 0.166m/s

Answer 2

V= 3 t²-4t+2

when t=2s

By derivating

6t-4+0 = 6t-4

t=2 s = 12-4=8ms^-1

Acceleration = velocity/time

8/2=4ms^-2