The velocity v of a particle at time t is given by v = at + b/t + c, where a, b and c are constants, the dimensions of a, b and c are?
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1
Answer:
LT−2, L and T
L2, T and LT2
LT2, LT and L
L, LT and T2
Answer :
A
Solution :
[a]=[vt]=LT−1T=LT−2,[C]=[t]=T
[b]=[vt]=LT−1T=L
Step-by-step explanation:
Answered by
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Step-by-step explanation: v=at+b/t+c
We know that, Two entities can only be added if their dimensions are same,
so Dimensions of [at] = Dimensions of [b/t] = Dimensions of [c] = Dimensions of [v]
=> [aT] = [v] = [LT⁻¹]=> [a] = [LT⁻²] , Dimensions of [a]
=>[bT⁻¹] = [LT⁻¹]=> [b] = [L], Dimensions of [b]
=> [c] = [LT⁻¹] , Dimensions of [c]
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