The velocity (v) - time (1) graph of an object moving along a straight line is as shown in Fig. 2(b).29. Calculate the distance covered by object between (i) t = 0 to t = 5 s (ii) t = 0 to t = 10 s.
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Step-by-step explanation:
Distance travelled in 0 to 5 s
= Area of trapezium OAB
= 1/2×(sum of parallel sides)×height
= 1/2×[(5-0)+(5-2)]×20 m
= 1/2×(5+3)×20 m
= 1/2×8×20 m
= 80 m
Likewise Distance travelled in 0 to 10 s
=Area of trapezium OAB + Area of triangle BC
=80 + 1/2×b×h
=80 + 1/2×(10-5)×20 m
=80 + 1/2×5×20 m
=80 + 50 m
=130 m
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