Question

the velocity (v) WITH TIME (T) of moving particle is given by v=4t. the acceleration of particle at t=3 s is

Answer 1

Answer:

In The Above Question The Equation Given Is v = 4t

So, If We Differentiate The Above Equation With Respect To t We Get,

dvdt=4dvdt=4

But dvdt=advdt=a (Acceleration)

So, a=4ms−2ms-2               -> (ii)

Now As The Equation (ii) is independent of time t

So, At Any Point Of Time The Acceleration Will be 4ms−2ms-2

So At Time t=3 seconds Acceleration a = 4ms−2ms-2

Thanks And Regards

Please mark me as the brainliest

Answer 2

Answer:

a=dv/dt

a=4

acceleration is 4 m/s^2