Question

the velosity of a particle moving along the x axis varies according to the expression Vx=40-5t2 whereVx is metre per second and t is in seconds the average accelaration in the time interval t=0 to t=2s is

Answer 1

Answer:

Acceleration a = dV÷ dt, the differentiation of velocity with respect to time is called as acceleration.

Acceleration a = -10t

For finding the average acceleration we have to integrate it from 0 to 2 and dividing it by time taken.

∫-10t= -5t² = -20

average acceleration = 20÷ 2 = 10m÷s²