Question

the verices of a square is a(1,2) b(5,4) c(3,8) d(-1,6) find the side of the square and area​

Answer 1

Step-by-step explanation:

refer to the attachment

Answer 2

$given \\ a (1 \: 2)\\ b(5 \: 4) \\ c( 3 \: 8)\\ d ( - 1 \: 6)$

$we \: know \: that \: from \: \\ section \: formula \: \\ ab = \sqrt{ ({x - y})^{2} + {(x1 - x2)}^{2} } \\ side \: of \: squre \: \\ ab = \sqrt{ ({5 - 1})^{2} + ({4 - 2})^{2} } \\ ab = \sqrt{ {4}^{2} + {2}^{2} } \\ ab = \sqrt{20} \\ area \: of \: square = {side}^{2} = { \sqrt{20} }^{2} = 20unit^2$