Physics, asked by saviovarghese4615, 10 months ago

The vernier constant of a vernier callipers is 0.001 cm. If 49 main scale divisions coincide with 50 vernier scale devisions, then the value of 1 main scale divisions is .

Answers

Answered by Jasleen0599
7

The value of 1 main scale divisions of the given vernier callipers is 0.05 cm.

- Vernier constant is defined as the ratio of the smallest division of the main scale to the number of divisions on the vernier scale.

- Hence,

0.001 cm=  Smallest division on main scale / 50  

⇒1 MSD = (0.001 × 50) = 0.05 cm .

Answered by ayush09bisht09
3

Vernier constant of a travelling microscope is 0:001 cm. If 49 main scale divisions coincide with 50 Vernier scale divisions, then the value of 1 main scale division is

answer

0.5 mm

#P.W

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