the Vertical angle of an isosceles triangle is 100 degree find its base angle.
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80° will be it's base angle
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Consider an isosceles ΔABC such that AB=AC Given that vertical angle A is 100°. Given to find the base angles Since ΔABC is isosceles ∠B=∠C [Angles opposite to equal angles are equal] And also, Sum of the interior angles of a triangle = 180°
A+B+C=180
100+B+C=180
2(angle B)= 180-100
=80/2
= 40
Angle B=Angle C= 40°
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