the vertical angle of an isosceles triangle is 100degree find its base angle
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Hey in the figure shown above
In triangle ABC
AB=AC(Sides of isosceles triangle)
Angle A=Angle B (Angles opposite to equal sides are equal
Let A=B=x
A+B+C=180 (angle sum property)
100+x+x=180
2x=80
x=40
So, B=C=40
In triangle ABC
AB=AC(Sides of isosceles triangle)
Angle A=Angle B (Angles opposite to equal sides are equal
Let A=B=x
A+B+C=180 (angle sum property)
100+x+x=180
2x=80
x=40
So, B=C=40
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sujeetbhk382:
thanx
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