the Vertical angle of an isosceles triangle is 110 degree what must be the size of each of its base angles
Answers
Answered by
5
Answer:35°
Step-by-step explanation:
110°+x+x=180°
2x=70°
Or=35°
Answered by
10
In an isosceles triangle 2 sides are equal and the angles opposite to them are also equal
then both the base angles will be same
let the base angle be x
then,
110+x+x=180
2x=180-110
2x=70
x=35
therefore the base angles is 35°
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