the vertical angle of an isosceles triangle is 80degree . find it's base angle.
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the vertical angle of an isosceles triangle is 80degree . find it's base angle.
→80° + x + x = 180
- 80 + 2x = 180
- 2x = 180-80
- 2x = 100
- x = 100/2
- x = 50
•°• The base angles of isosceles triangle is 50°.
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0
Answer:
50 degrees
Step-by-step explanation:
The vertical angle = 80 degrees. The first thing you have to do is remember that sum of angles of triangle is 180 degrees. The second thing is that opposite angles of equal angles are equal.
vertical angle + isosceles angle 1 +isosceles angle 2
80+2x=180(x= base isosceles angle)
100=2x
x=50 degree
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