Math, asked by advaypoddar04072007, 11 months ago

The vertical angle of an isosceles triangle is three times the sum of its base angles. Find each angle of the triangle.

Answers

Answered by balwani
12

Step-by-step explanation:

Let each base angle of an isosceles, triangle = x

Then its vertical = 3 (x + x) = 3 × 2x = 6x.

∴ 6x + x + x = 180°

(Sum of angles of a triangle)

⇒ 8x = 180° ⇒ x = 180°/8 = 22.5°

∴ Each base angle = 22.5°

And vertical angle = 3 × (22.5 + 22.5)

= 3 × 45 = 135°

Answered by imperialxak47
7

Answer:

base angles 22.5 and top angle 135.......

Step-by-step explanation:

Let each base angle of an isosceles, triangle = x

Then its vertical = 3 (x + x) = 3 × 2x = 6x.

∴ 6x + x + x = 180°

(Sum of angles of a triangle)

⇒ 8x = 180° ⇒ x = 180°/8 = 22.5°

∴ Each base angle = 22.5°

And vertical angle = 3 × (22.5 + 22.5)

= 3 × 45 = 135°

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