The vertical height and length of base of squared based pyramid are in the ratio of 2:3. If the total surface area of the pyramid is 384 cm find the slant height.
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Ans 10cm
Step-by-step explanation:
Given
T.S.A=384cm^2
base of length(a)= 3x cm
vertical height ( h)= 2x cm
now, slant height (l)= ✓(2x)^2+(3x/2)^2
=✓4x^2+9x^2/4 taking l.c.m
=✓(16x^2+9x^2)/4
=✓25x^2/4
=✓( 5x/2)^2
= 5x/2
now , T.S.A= 2al+ a^2
384= 2*3x*5x/2+(3x)^2
or 384 = 15x^2+9x^2
or 384= 24x^2
or x^2=383/24
or x^2= 16
or x= 4
again l= 5x/2
= 5*4/2
= 20/2
= 10cm.
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