Question

The vertical pole of length 6M casts a shadow 4m long on the ground at the same time a tower casts a shadow 28 m long find the height of the tower.​

Answer 1

length of shadow= 28m
therefore the height of tower= 42 metre

Answer 2

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Given,

Length of the vertical pole = 6 m

Shadow of the pole = 4 m

Let the height of the tower be h m.

Length of the shadow of the tower = 28 m

Class 10 Maths Chapter 6 Triangles 04

In ΔABC and ΔDFE,

∠C = ∠E (angle of elevation)

∠B = ∠F = 90°

By AA similarity criterion,

ΔABC ~ ΔDFE

We know that the corresponding sides of two similar triangles are proportional.

AB/DF = BC/EF

6/h = 4/28

h = (6 ×28)/4

h = 6 × 7

h = 42

Hence, the height of the tower = 42 m

Hope it's Helpful....:)