Question

The vertices of a triangle ABC are A(3,8) , B(-1,2) , C(6,-6). Find:
(i) slope of BC
(ii) equation of a line perpendicular to BC and passing through A.​

Answer 1

Answer:

-8/7

8y = 7x + 43

Step-by-step explanation:

The vertices of a triangle ABC are A(3,8) , B(-1,2) , C(6,-6). Find:

(i) slope of BC

(ii) equation of a line perpendicular to BC and passing through A.​

Slope of line BC = (-6-2)/(6-(-1)) = 8/-7  = -8/7

a line perpendicular to BC

Slope of line perpendicular to BC * Slope of line BC = -1

=> Slope of line perpendicular to BC * (-8/7) = -1

=> Slope of line perpendicular to BC = 7/8

Equation of line

y = 7x/8 + c

passing through A (3,8)

=> 8 = 7*3/8 + c

=> c = 8 - 21/8

=> c = 43/8

y = 7x/8 + 43/8

=> 8y = 7x + 43