The vertices of a triangle are A(10,4), B(4,-9), C(-2,-1). Find the equation of the altitude through A.
Answers
Answered by
57
Hope it helps............
Attachments:
tokaians:
the answer at the back is given as 3x-4y-14=0
Oh let me recheck my answer.
ok
Ya my slope is wrong.
The slope will be 3/4
u can edit it
No I can't
You've thanked me already
ok
An answer can't be edited after a thanks
Answered by
102
The vertices of a triangle are A(10,4), B(4,-9), C(-2,-1).
Slope of BC = (-1+9)/(-2-4) = 8/(-6) = -4/3
For altitude from A to BC,
m1 m2 = -1
⇒ (-4/3) × m2 = -1
⇒ m2 = 3/4
The equation of altitude is
⇒y - y' = slope ( x - x')
⇒y - 4 = 3/4 ( x - 10) [ slope = m2]
⇒4y - 16 = 3x - 30
⇒4y - 3x +14 = 0
∴The equation of altitude from A is :
4y - 3x +14 = 0
⇒ 3x - 4y - 14 = 0
Slope of BC = (-1+9)/(-2-4) = 8/(-6) = -4/3
For altitude from A to BC,
m1 m2 = -1
⇒ (-4/3) × m2 = -1
⇒ m2 = 3/4
The equation of altitude is
⇒y - y' = slope ( x - x')
⇒y - 4 = 3/4 ( x - 10) [ slope = m2]
⇒4y - 16 = 3x - 30
⇒4y - 3x +14 = 0
∴The equation of altitude from A is :
4y - 3x +14 = 0
⇒ 3x - 4y - 14 = 0
it's not clear
i hope now it is clear
mark it as brainliest
Similar questions