Question

The vertices of a triangle are A(3,4), B(2,0)
nd C(-1,6). Find the equations of the lines
containing
(a) side BC (b) the median AD
(c) the mid points of sides AB and BC.​

Answer 1

Answer:

Step-by-step explanation:

Answer: The vertices are A(11,12), B(1,2) and C(5,6).

Step-by-step explanation: As shown in the figure, let A(a,b), B(c,d) and C(e,f) be the vertices of ΔABC.

Given that D(3,4), E(8,9) and F(6,7) are the mid-points of the sides BC, CA and AB respectively.

Since D is the mid-point of BC, so

Similarly, since F is the mid-point of AB, so

∴ Also, since E is the mid-point of AC, so

Solving the above linear equations, we get

Thus, the vertices of ΔABC are A(11,12), B(1,2) and C(5,6).