The vertices of a triangle are A(-5,3),B(p,-1),C(6,q).Find the values of p and q if the centroid of the triangle ABC is the point (1,-1).
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We have, A(−5,3); B(p,−1) and C(6,q) are the given vertices of triangle.
Now, we know that centroid of a triangle C(x,y) having its vertices at (x1,y1); (x2,y2) and (x3,y3) isx = x1+x2+x33 and y = y1+y2+y33
Now, 1 = −5+p+63 ⇒ p = 2and −1 = 3−1+q3⇒q = −5
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