the vertices of parallelogram ABCD are A(-2,3),B(6,7),C(8,X) and D(y,-1) then x-y =
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x - y = 6
M of AC = M of BD
(3, (x+3) / 2) = ((6+y) / 2, 3)
6 + y = 3
y = -3
(x + 3) / 2 = 3
x + 3 = 6
x = 3
x - y = 3 - (-3)
= 6
M of AC = M of BD
(3, (x+3) / 2) = ((6+y) / 2, 3)
6 + y = 3
y = -3
(x + 3) / 2 = 3
x + 3 = 6
x = 3
x - y = 3 - (-3)
= 6
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