Question

the vertices of square defg are on the sides of triangle abc angle a=90 prove that de square =​

Answer 1

Answer:

Given

DEFG is a square

To prove : DE

2

=BD×EC

∠GDB=∠GAF=90

o

(given)

∠AGF=∠GBF (corresponding ,GF || BC and AB is a transversal line ).

By AA test of similarity

ΔGBD∼ΔAGF

∴

DE

CE

=

BD

FE

⇒

DE

CE

=

BD

DE

⇒DE

2

=BD×CE

Hence proved.

Answer 2

Answer:

I think this is not complete question. Please send the complete and proper question then I can help you.