the vertices of square defg are on the sides of triangle abc angle a=90 prove that de square =
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0
Answer:
Given
DEFG is a square
To prove : DE
2
=BD×EC
∠GDB=∠GAF=90
o
(given)
∠AGF=∠GBF (corresponding ,GF || BC and AB is a transversal line ).
By AA test of similarity
ΔGBD∼ΔAGF
∴
DE
CE
=
BD
FE
⇒
DE
CE
=
BD
DE
⇒DE
2
=BD×CE
Hence proved.
Answered by
0
Answer:
I think this is not complete question. Please send the complete and proper question then I can help you.
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