Write the value of n for which the numbers 3n , 5n+7 and 9n -2 are in A.P.
Answers
Answered by
1
Answer:
n=1
STEP BY STEP EXPLANATION:-
let us assume that the given nos. are in ap
Now since,3n, 5n+7 and 9n-2 are in ap
then, their common difference will be same
therefore
5n+7-3n=9n-2-5n+7
2n+7=4n+5
2n=2
n=1
Answered by
0
Answer:
Step-by-step explanation:
let 3n=a1, 5n+7=a2, 9n-2=a3
2*a2=a1+a3
2*(5n+7)=3n+9n-2
10n+14=12n-2
1 4+2=12n-10n
16=2n
n=16/2
n=8
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