Question

the vertices of triangle ABC are A(1,1) B(-3,4),C(2,-5) the equation of the altitude through vertex A is​

Answer 1

$\text{Given points are A(1,1) B(-3,4) and C(2,-5)}$

$\text{Slope of the line joining B and C}$

$=\displaystyle\frac{y_2-y_1}{x_2-x_1}$

$=\displaystyle\frac{-5-4}{2+3}$

$=\displaystyle\frac{-9}{5}$

$\implies\;\textbf{Slope of BC}=\displaystyle\frac{-9}{5}$

$\text{Then,}$

$\text{Slope of the altitude from A is}\displaystyle\frac{5}{9}$

$\text{The equation altitude from A is}$

$y-y_1=m(x-x_1)$

$y-1=\frac{5}{9}(x-1)$

$9y-9=5x-5$

$\implies\boxed{\bf\,5x-9y+4=0}$

$\therefore\textbf{The equation of altitude from A is 5x-9y+4=0}$

Answer 2

Answer:

5x-9y+4=0

Step-by-step explanation:

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