The vertices of triangle R'S'T' are R'(1, 3), S'(6, 4), and T'(4, 2). If triangle RST was dilated about the origin with a scale factor of 3, what are the coordinates of its vertices?
Answers
Answered by
0
"For the above question the answer is C, R(3,9), S(18,12), T(12,6). This is because the original vertices are:
R' (1,3)
S' (6,4)
T' (4,2)
The vertices are now dilated with the scale factor which is 3. Then the results will be as follows:
R(3,9)=1 x 3 = 3 ; 3 x 3 = 9
S(18,12)=6 x 3 = 18 ; 4 x 3 = 12
T(12,6) =4 x 3 = 12 ; 2 x 3 = 6
"
Answered by
0
the answer is 16
Explanation:
if R'S'T' has a leg with a length of 8 and this was caused by RST being divided in half (1/2) that means we must multiply 8 by 2 to find the whole = 16
We can check by finding the 1/2 of 16, which gives us 8.
Similar questions