Question

the virus of a culture decreases at the rate of 5% due to a medicine have the virus count in the culture at 10:00 a.m.was 2.3 into 10 to the power 7 find the discount at 1:00 p.m. on the same day

Answer 1

Answer:

The virus count at 1:00 PM is $1.97\times 10^7$

Step-by-step explanation:

Assuming that the virus is decreasing at the rate of 5% per hour

If the initial number of virus are N and the rate of decreasing is r then after n hours, the virus remaining will be

$N'=N(1-\frac{r}{100})^n$

From 10 AM to 1 PM total number of hours passed = 3

Given $N=2.3\times 10^7$

$r=5\%$

Thus,

$N'=N(1-\frac{r}{100})^n$

$N'=2.3\times 10^7(1-\frac{5}{100})^3$

$\implies N'=2.3\times 10^7(1-\frac{1}{20})^3$

$\implies N'=2.3\times 10^7(\frac{19}{20})^3$

$\implies N'=2.3\times 10^7\times \frac{6859}{8000}$

$\implies N'=1.97\times 10^7$

Hope this helps.

Answer 2

Answer:

use the process of A= p ( 1-r/100)

Step-by-step explanation:

answer us 1.97 * 10⁷