The volime of 1.0 g of hydrogen in litres at NTP is
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1 mole of gas at NTP occupies = 24.04 L
No. of moles of H2 in 1g = mass / molar mass =1/2 =0.5 moles
Volume of 0.5 moles of gas = 0.5 x 24.04 L = 12.02 L
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No. of moles of H2 in 1g = mass / molar mass =1/2 =0.5 moles
Volume of 0.5 moles of gas = 0.5 x 24.04 L = 12.02 L
Hope this helps you and if you find it useful pls mark mine as brainliest :)
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