the voltage across the lamp is 6 plus or minus 0.1 volt and current through it is 4 plus or minus 0.2 ampere find the power consumed with maximum permissible error in it
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hope it helps you na na ana
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Darshinirajarajan:
thnx
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Hi..
Power = VI
P = 6*4 = 24 Watt
dP = P(dV/V + dI/I)
dP = 24*(0.1/6 + 0.2/4)
dP = 1.6
Power consumed = (24 ± 1.6) Watt.
Hope this helps u!!
Power = VI
P = 6*4 = 24 Watt
dP = P(dV/V + dI/I)
dP = 24*(0.1/6 + 0.2/4)
dP = 1.6
Power consumed = (24 ± 1.6) Watt.
Hope this helps u!!
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