Question

The voltage between the terminals of a battery is 6 v. When a wire is connected across its terminals, it fall to 5.6 v. If one more identical wire is connected between the terminals, then it will fall to

Answer 1

Answer. 5.25 V

Explanation:

5.6=$(\frac{E}{R+r} )R$     (1)

5.6(R+r)= 6R

0.4R=5.6r

R=$\frac{56}{4}r$ = 14r

V= $\frac{E}{(R/2+r)}$  ×$\frac{R}{2}$ = $\frac{ER}{R+2}$

V= (6×14r)/14r+2r = 6×14/16=21/4=5.25

V= 5.25V