the voltage drop across a capacitor connected with a resistance and a battery of 60V in series after a long time
a. 0V
b. 60V
c. 30V
d. 38V
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3
Answer:
t = infinite (after long time)
i = 0 ; open circuit
Voltage across capicitor is 0V
No charge charge flow it
As you know
V = q/c
q-0
V= 0
Where as t = 0sec
capicitor replaced by straight wire
I = max
V= 60V
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