Question

the voltage drop across a capacitor connected with a resistance and a battery of 60V in series after a long time
a. 0V
b. 60V
c. 30V
d. 38V​

Answer 1

Answer:

t = infinite (after long time)

i = 0 ; open circuit

Voltage across capicitor is 0V

No charge charge flow it

As you know

V = q/c

q-0

V= 0

Where as t = 0sec

capicitor replaced by straight wire

I = max

V= 60V