Question

The voltage v and current i in an ac circuit are given by v = 50 sin 50t v and i= 50 sin(50t+ pi/3) the power dissipated in circuit is

Answer 1

heyy harsh ur answer..........

            power=i^2×R......(R=V/i)..

              p=50^2×50/50
            p=2500...

      @kundan

Answer 2

Answer:

Power dissipated, P = 625 watts

Explanation:

It is given that,

Voltage, $V=50\ sin(50t)$

Current, $I=50\ sin(50t+\pi/3)$

We have to find the power dissipated in the circuit. Mathematically, it can be written as :

$P=\dfrac{V_oI_o}{2}\ cos\phi$

Here, V₀ = I₀ = 50 and cosφ = π/3

So, power becomes $P=\dfrac{(50)^2}{2}\ cos(\dfrac{\pi}{3})$

P = 625 watts

Hence, this is the required solution.