The volume and base area of a right circular cone are 48π cm^3 and 12π cm^2 respectively,then the height of the cone is? pls with steps
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Given that,
V = 48π cm³
and A = 12π cm³
Let the radious be r cm
and height be h cm
Therefore πr² = 12π
=> r² = 12
=> r = 2√3
Therefore,volume = ⅓π(2√3)²×h
But, given that volume = 48π
So, ⅓π(2√3)²×h = 48π
=> ⅓ × 12 × h = 48
=> 4h = 48
=> h = 12 cm
Therefore, height of the cone = 12 cm.
That's it
Hope it helped ❤(ӦvӦ。)
V = 48π cm³
and A = 12π cm³
Let the radious be r cm
and height be h cm
Therefore πr² = 12π
=> r² = 12
=> r = 2√3
Therefore,volume = ⅓π(2√3)²×h
But, given that volume = 48π
So, ⅓π(2√3)²×h = 48π
=> ⅓ × 12 × h = 48
=> 4h = 48
=> h = 12 cm
Therefore, height of the cone = 12 cm.
That's it
Hope it helped ❤(ӦvӦ。)
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