Question

the volume gas at ntp produced by 100 gmbog CaC2 with water :
CaC2 +2H2O ----> Ca(OH)2+C2H2

Answer 1

CaC2+2H2o ---Ca(OH)2+C2H2. Means 1mole of cac2 gives 1mole of acetylene or 22.4 lit of gasNow 64g of CaC2 gives 22.4 lit. So 100g of CaC2 gives 22.4* 100/64 = 35 lit of gas ( here * used for multiplication

Answer 2

Answer: The volume of gas at ntp produced by 100 g of $CaC_2$ with water is 35 L.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at NTP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of}CaC_2=\frac{100g}{64g/mol}=1.56moles$  

$CaC_2+2H_2O(l)\rightarrow Ca(OH)_2(aq)+C_2H_2(g)$

According to stoichiometry,

1 mole of $CaC_2$ gives 22.4 L of $C_2H_2$ at NTP

1.56 moles of $CaC_2$ gives =$\frac{22.4}{1}\times 1.56=35 L$ of $C_2H_2$ at NTP