Question

The volume ( in ml ) 50 vol of h202 required which on decomposition gives sufficient oxygen for complete combustion of 100ml of ethane at stp

Answer 1

7 ml $H_{2} O_{2}$

Explanation:

The reaction:

$C_{2} H_{6} + 7/2 O_{2}$ → $2CO_{2} + 3H_{2}O$

Volume of $O_{2}$ = 7/2 * 100

= 350 ml

So, From 1 ml of 50 Vol of $H_{2} O_{2}$, we get 50 ml of $O_{2}$

Now for 350 ml of $O_{2}$, we require

⇒ 350/50ml

= 7 ml $H_{2} O_{2}$

∵ Thus, 7 ml  $H_{2} O_{2}$ is required for complete combustion of 100 ml ethane.

Learn more: STP

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