Question

the volume occupied by 1.4 g of N2 at stp is?​

Answer 1

Answer:

The volume of 1.4 g N2 at STP is 1.12L

Explanation:

At STP N2 is 22.4L and 28g

So, 28g N2=22.4L

Now, 1.4g N2=(22.4÷28)×1.4L=1.12 L.

That's all.

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Answer 2

Answer:

1.12L

Explanation:

Gram molecular mass of N2=14×2=28g

28g of N2 occupies 22.4L at STP

1g of N2 occupies 22.4/28L at STP

So, 1.4g of N2 occupies 22.4×1.4/28L

=1.12L (ans)

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