The volume occupied by 1.4g of Nz at STP is:
a) 2.24 dm3
22.4 dm3
1.12 dm3
112 dm3
Answers
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Answer:
1.12 dm3
Explanation:
1 mole occupy 22.4dm3
N2 atm weight = 28g
moles of N2 = 1.4/28 = 1/20
hence V = 1/20 * 22.4 = 1.12 dm3
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