Question

The volume occupied by 1 mole of gas at 1 bar pressure and 273.15K is.....

Answer 1

n = 1mole

P = 1bar

T = 273.15K

V = ?

PV = nRT

V = nRT/P

= 1 × 8.3 × 273.15 / 1

V = 2267.14


Thanks

Answer 2

Answer:

22.711 lit

Explanation:

At 1 bar pressure and 273.15 K, volume of 1 mole of gas 22.711 lit